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Lake Alfred, FL
Full City Profile · Florida · Osceola County County
3.3
/5.0
B
Good
6,803
Population
324/sq mi density
$68,854
Median Income
$32,738 per capita
$226,800
Home Value
$306,047 Zillow
$1,348
Median Rent
34.6% income on rent
75°F
Avg Temperature
330 sunny days/yr
49
Violent Crime/100K
604 property/100K
B
Overall
3.3 / 5.0
Good overall score based on economy, affordability, safety and education
A
Economy
4.3 / 5.0
$68,854 median income, 2.6% unemployment
A+
Affordability
4.8 / 5.0
$226,800 home value, $1,348/mo rent
F
Safety
1.0 / 5.0
49 violent crimes/100K
B
Education
3.0 / 5.0
25.0% bachelor's degree or higher
Crime Overview
Violent Crime Rate
49
per 100,000 residents
87% below
US avg: 380/100K
Property Crime Rate
604
per 100,000 residents
69% below
US avg: 1,960/100K
Safety Rating
Very Low Crime
Safety grade: F (1.0/5.0)
Violent Crime Breakdown
Per 100,000 residents. Thin line = U.S. average.
Murder
0.0
avg 6.3
Rape
0.0
avg 40.0
Robbery
0.0
avg 73.9
Assault
49.0
avg 268.5
Property Crime Breakdown
Per 100,000 residents. Thin line = U.S. average.
Burglary
196.0
avg 271.0
Theft
343.0
avg 1,401.9
Vehicle Theft
65.3
avg 282.7
Arson
0.0
Complete Crime Data
Violent Crime (per 100K)
| Total Violent Crime | 49.0 |
| Murder | 0.0 |
| Rape | 0.0 |
| Robbery | 0.0 |
| Aggravated Assault | 49.0 |
Property Crime (per 100K)
| Total Property Crime | 604.3 |
| Burglary | 196.0 |
| Theft/Larceny | 343.0 |
| Vehicle Theft | 65.3 |
| Arson | 0.0 |
Traffic Safety
| Fatal Crashes (County) | 70 |